On DB2, group by substr(XXXX,1,3) is not accepted. So, by the way.
SELECT b.SUB, COUNT(*)
FROM TABLEA a JOIN
(SELECT DISTINCT SUBSTR(ID,1,1) AS SUB
FROM TABLEA) b ON SUBSTR(a.ID,1,1) = b.SUB
GROUP BY b.SUB
On DB2, group by substr(XXXX,1,3) is not accepted. So, by the way.
SELECT b.SUB, COUNT(*)
FROM TABLEA a JOIN
(SELECT DISTINCT SUBSTR(ID,1,1) AS SUB
FROM TABLEA) b ON SUBSTR(a.ID,1,1) = b.SUB
GROUP BY b.SUB
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